Bonjour jaurai besoin d'aide s'il vous plaît merci.... Pergunta de ideia depriscillamorel1

January 2021 1 110 Report

Bonjour jaurai besoin d'aide s'il vous plaît merci

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Bonjour,
g(x)=-0.1x²+1.4x+1.5
-0.1(x+1)(x-15)=-0.1(x²+x-15x-15)
-0.1(x²-14x-15)=-0.1x²+1.4x+1.5
g(x)=-0.1(x+1)(x-15)

-0.1(x-7)²+32/5=-0.1(x²-14x+49)+6.4
-0.1x²+1.4x-4.9+6.4
-0.1x²+1.4x+1.5
g(x)=-0.1(x-7)²+32/5

g(0)=-0.1(0²)+1.4(0)+1.5
g(0)=1.5

g(7)=-0.1(x-7)²+32/5
g(7)=-0.1(0)²+32/5
g(7)=32/5
g(7)=6.4

g(x)=1.5
-0.1x²+1.4x+1.5=1.5
-0.1x+1.4x=1.5-1.5
-0.1x²+1.4x=0
x(-0.1x+1.4)=0     x=0
                         -0.1x+1.4=0 -0.1x=-1.4 x=1.4/0.1 x=14

g(x)=-0.1(x+1)(x-15)
x               -∞            -1                        +15                 +∞
x+1                      -         0         +               +         +
x-15                  -                     -                0        +
-0.1(x+1)(x-15)       -          0         +               0         -

g(x)≥0 x ∈[-1,+15]

g(x)=-0.1x²+1.4x+1.5

a<0   alors g(x) admet un maximum
a(x-α)²+β
(α;β) coordonnées du maximum
α=-b/2a
α=1.4/-0.2
α=7
β=g(α)
β=g(7)
g(7)=6.4
voir plus haut
β=6.4
maximum(7;6.4)

hauteur maximale 6.4

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