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Annaaiiss
@Annaaiiss
May 2019
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Bonjour j'aurais besoin d'aide pour des maths s'il vous plaît
1) factoriser A(x)=(6-x)²-(6-x)(6-2x)
2) factoriser l'expression B(x)=9-A(x)
merci de votre aide
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Commentaires (1)
Bonjour,
1) factoriser A(x)=(6-x)²-(6-x)(6-2x)
(6-x)(6-x-6+2x) =
(6-x)(x) =x(6-x)
2) factoriser l'expression B(x)=9-A(x)
9-x(6-x) =
9-6x+x² =
x²-6x+9=
(x-3)² c'est factorisé
2 votes
Thanks 1
Annaaiiss
merci beaucoup !!
telephone16
Factorisation
(6 -x)
² -
(6 -x)
(6 -2x)
(6-x) (6 -x -6+2x)
(6-x) ( x)
9-A(x)
9 -x (6-x)
9- 6x +x² cela donne
x² -6x +9
(x-3)²
1 votes
Thanks 1
Annaaiiss
merci beaucoup!!
telephone16
bonne semaine !
Annaaiiss
merci à vous aussi :)
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Lista de comentários
1) factoriser A(x)=(6-x)²-(6-x)(6-2x)
(6-x)(6-x-6+2x) =
(6-x)(x) =x(6-x)
2) factoriser l'expression B(x)=9-A(x)
9-x(6-x) =
9-6x+x² =
x²-6x+9=
(x-3)² c'est factorisé
(6 -x)² - (6 -x) (6 -2x)
(6-x) (6 -x -6+2x)
(6-x) ( x)
9-A(x)
9 -x (6-x)
9- 6x +x² cela donne
x² -6x +9
(x-3)²