1) a. DM b. CM c. BM
Appliquons le théorème de PYTHAGORE
AM² = AD² + DM² ⇒DM² = AM² - AD²
= 32² - 19.2²
= 1024 - 368.64
= 655.36
DM = √655.36 = 25.6 cm
b) DC = DM + MC ⇒ MC = DC - DM (DC = AB)
= 40 - 25.6 = 14.4 cm
MC = 14.4 cm
c) on applique PYTHAGORE
BM² = BC² + MC² (BC = AD)
= 19.2² + 14.4²
= 368.64 + 207.36
= 576
BM = √576 = 24 cm
2) Réciproque du théorème de PYTHAGORE
AM² + MB² = 32² + 24²
= 1024 + 576
= 1600
AB = 40 et AB² = 40² = 40 x 40 = 1600
Donc le triangle AMB est rectangle en M
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
1) a. DM b. CM c. BM
Appliquons le théorème de PYTHAGORE
AM² = AD² + DM² ⇒DM² = AM² - AD²
= 32² - 19.2²
= 1024 - 368.64
= 655.36
DM = √655.36 = 25.6 cm
b) DC = DM + MC ⇒ MC = DC - DM (DC = AB)
= 40 - 25.6 = 14.4 cm
MC = 14.4 cm
c) on applique PYTHAGORE
BM² = BC² + MC² (BC = AD)
= 19.2² + 14.4²
= 368.64 + 207.36
= 576
BM = √576 = 24 cm
2) Réciproque du théorème de PYTHAGORE
AM² + MB² = 32² + 24²
= 1024 + 576
= 1600
AB = 40 et AB² = 40² = 40 x 40 = 1600
Donc le triangle AMB est rectangle en M