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Merii
@Merii
January 2021
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Bonjour, j'aurais besoin d'aide pour un dm de maths de seconde. C'est pour demain donc c'est urgent. Voilà merci à qui m'aidera.
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trudelmichel
Verified answer
Bonjour,
Df(x)=[-6;6]
f(-2)=-1
f(4)=0
f(6)=-4
f(-5) et f(-3)
si -6<x<-2 alors f(x) croissante
-5<-3
f(-5)<f(-3)
MAXf(x)=10
MINf(x)=-4
f(0)
-2<0<4
si -2<x<4 alors f(x) croissante
alors f(-2)<f(0)<f(4)
d'où
-1<f(0)<0
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Merii
merci
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Lista de comentários
Verified answer
Bonjour,Df(x)=[-6;6]
f(-2)=-1
f(4)=0
f(6)=-4
f(-5) et f(-3)
si -6<x<-2 alors f(x) croissante
-5<-3
f(-5)<f(-3)
MAXf(x)=10
MINf(x)=-4
f(0)
-2<0<4
si -2<x<4 alors f(x) croissante
alors f(-2)<f(0)<f(4)
d'où
-1<f(0)<0