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Babyshamalowx
@Babyshamalowx
May 2019
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Bonjour, j'aurais besoin que l'on m'aide sur cet exercice de maths !! Merci d'avance !
La fonction g est définie par g (x) = 5x + 1
a) qu'elle est l'image de 5 par la fonction g ?
b) détermine g (0) ; g ( -2,1 ) et g ( 7 ).
c) determine les antécédents, par la fonction g, des nombres 21 ; -14 et 0.
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Commentaires (2)
Bonjour
g(x) = 5 x + 1
a) g(5) = 25 + 1 = 26
b) g(0) = 1
g( - 2.1) = -10.5 +1 = - 9.5
g (7) = 36
antécédent de 21
5 x + 1 = 21
5 x = 20
x = 4
antécédent de - 14
5 x - 1 = - 14
5 x = - 13
x = - 13/5
antécédents de 0
5 x + 1 = 0
5 x = - 1
x = - 1/5
2 votes
Thanks 1
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g(x) = 5 x + 1
a) g(5) = 25 + 1 = 26
b) g(0) = 1
g( - 2.1) = -10.5 +1 = - 9.5
g (7) = 36
antécédent de 21
5 x + 1 = 21
5 x = 20
x = 4
antécédent de - 14
5 x - 1 = - 14
5 x = - 13
x = - 13/5
antécédents de 0
5 x + 1 = 0
5 x = - 1
x = - 1/5