Articles
Register
Sign In
Search
Devoir93921
@Devoir93921
May 2019
1
52
Report
Bonjour Je comprend pas l’exercice si dessou merci d’avance bonne soirée
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
AhYan
Bonsoir,
1. Distance horizontale (DH) = 2 × altitude (A)= 2×300 = 600m
Avec le Théorème de Pythagore :
Distance parcourue (DP)² = A² + DH²
DP² = 300² + 600²
DP² = 90 000 + 360 000
DP² = 450000
DP = √450 000 ≈ 670,82 mètres
2. 20m/s
Vitesse = Distance/Temps => T = D/V
670,82/20= 33,5 secondes
1 votes
Thanks 2
Devoir93921
Merci beaucoup de m’avoir répondue bonne soirée
AhYan
De rien, bonne soirée !
TheTigerRoaa
Bonne soirée :-)
More Questions From This User
See All
Devoir93921
January 2021 | 0 Respostas
Responda
Devoir93921
January 2021 | 0 Respostas
Responda
Devoir93921
January 2021 | 0 Respostas
Responda
Devoir93921
January 2021 | 0 Respostas
Responda
Devoir93921
January 2021 | 0 Respostas
Responda
Devoir93921
January 2021 | 0 Respostas
Responda
Devoir93921
January 2021 | 0 Respostas
Responda
Devoir93921
May 2019 | 0 Respostas
Responda
Devoir93921
May 2019 | 0 Respostas
Responda
Devoir93921
May 2019 | 0 Respostas
Responda
×
Report "Bonjour Je comprend pas l’exercice si dessou merci d’avance bonne soirée.... Pergunta de ideia de Devoir93921"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
1. Distance horizontale (DH) = 2 × altitude (A)= 2×300 = 600m
Avec le Théorème de Pythagore :
Distance parcourue (DP)² = A² + DH²
DP² = 300² + 600²
DP² = 90 000 + 360 000
DP² = 450000
DP = √450 000 ≈ 670,82 mètres
2. 20m/s
Vitesse = Distance/Temps => T = D/V
670,82/20= 33,5 secondes