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Devoir93921
@Devoir93921
May 2019
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Bonjour Je comprend pas l’exercice si dessou merci d’avance bonne soirée
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AhYan
Bonsoir,
1. Distance horizontale (DH) = 2 × altitude (A)= 2×300 = 600m
Avec le Théorème de Pythagore :
Distance parcourue (DP)² = A² + DH²
DP² = 300² + 600²
DP² = 90 000 + 360 000
DP² = 450000
DP = √450 000 ≈ 670,82 mètres
2. 20m/s
Vitesse = Distance/Temps => T = D/V
670,82/20= 33,5 secondes
1 votes
Thanks 2
Devoir93921
Merci beaucoup de m’avoir répondue bonne soirée
AhYan
De rien, bonne soirée !
TheTigerRoaa
Bonne soirée :-)
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Lista de comentários
1. Distance horizontale (DH) = 2 × altitude (A)= 2×300 = 600m
Avec le Théorème de Pythagore :
Distance parcourue (DP)² = A² + DH²
DP² = 300² + 600²
DP² = 90 000 + 360 000
DP² = 450000
DP = √450 000 ≈ 670,82 mètres
2. 20m/s
Vitesse = Distance/Temps => T = D/V
670,82/20= 33,5 secondes