Articles
Register
Sign In
Search
Cplyc
@Cplyc
May 2019
1
92
Report
Bonjour, je dois calculer la primitive de cette fonction (pièce jointe) mais je n'y arrive pas, pouvez-vous m'aider svp? Merci d'avance!
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
scoladan
Verified answer
Bonjour,
Soit F(x) = (ax + b)e(0,5x) + k
F'(x) = ae(0,5x) + 0,5(ax + b)e(0,5x)
= [a + 0,5b + 0,5ax]e(0,5x)
⇒ 0,5a = -1 ⇒ a = -2
et a + 0,5b = 5 ⇒ b = (5 - a)/0,5 = 2(5 - a) = 10 - 2a = 10 + 4 = 14
⇒ F(x) = (-2x + 14)e(0,5x) + k
On vérifie F'(x) = f(x)
1 votes
Thanks 1
cplyc
Merci beaucoup
More Questions From This User
See All
cplyc
January 2021 | 0 Respostas
Responda
Cplyc
May 2019 | 0 Respostas
Bonjour, comment dit-on "diluer au 1/100 et 1/10" en anglais svp? Merci d'avance
Responda
Cplyc
May 2019 | 0 Respostas
Responda
Cplyc
May 2019 | 0 Respostas
Responda
Cplyc
May 2019 | 0 Respostas
Responda
Cplyc
May 2019 | 0 Respostas
Responda
Cplyc
May 2019 | 0 Respostas
Responda
×
Report "Bonjour, je dois calculer la primitive de cette fonction (pièce jointe) mais je n'y arrive pas, pouv.... Pergunta de ideia de Cplyc"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjour,Soit F(x) = (ax + b)e(0,5x) + k
F'(x) = ae(0,5x) + 0,5(ax + b)e(0,5x)
= [a + 0,5b + 0,5ax]e(0,5x)
⇒ 0,5a = -1 ⇒ a = -2
et a + 0,5b = 5 ⇒ b = (5 - a)/0,5 = 2(5 - a) = 10 - 2a = 10 + 4 = 14
⇒ F(x) = (-2x + 14)e(0,5x) + k
On vérifie F'(x) = f(x)