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chtroufette
@chtroufette
June 2021
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Bonjour je dois, develloper ceci ( J'y arrive pas :( )
( 2x - 3 )² + ( 4x - 5 ) ( 4x +5 )
Merci
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arnouxe
Bonjour
(2x²-2*2x*3+3²)+(4x*4x+4x*5-5*4x-5*5)
=2x²-12+9+16x²+20x-20x-25
=18x²-22
0 votes
Thanks 1
Meysie
(2x - 3 )² + (4x - 5) (4x + 5)
il faut utiliser les identités remarquable à savoir :
(a-b)² = a² + b² - 2ab
(a - b) ( a + b) = a² - b²
donc :
(2x - 3)² = (2x)² + 3² - 2 * 2x * 3
(4x - 5) (4x + 5) = (4x)² - 5²
(2x - 3)² + (4x - 5) (4x+5)
= [ (2x)² + 3² - 2 * 2x * 3 ] + [ (4x)² - 5²]
et si tu veux factorisé pour résoudre ça fait :
= 4x² + 9 - 12x + 16x² - 25
= 20x² - 16 - 12x
1 votes
Thanks 1
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(2x²-2*2x*3+3²)+(4x*4x+4x*5-5*4x-5*5)
=2x²-12+9+16x²+20x-20x-25
=18x²-22
il faut utiliser les identités remarquable à savoir :
(a-b)² = a² + b² - 2ab
(a - b) ( a + b) = a² - b²
donc :
(2x - 3)² = (2x)² + 3² - 2 * 2x * 3
(4x - 5) (4x + 5) = (4x)² - 5²
(2x - 3)² + (4x - 5) (4x+5)
= [ (2x)² + 3² - 2 * 2x * 3 ] + [ (4x)² - 5²]
et si tu veux factorisé pour résoudre ça fait :
= 4x² + 9 - 12x + 16x² - 25
= 20x² - 16 - 12x