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hdih
@hdih
June 2021
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Bonjour, je dois développer une eixpression en maths la voilà : 3(x-5)(x+1)
J'ai besoin de votre aide.
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isapaul
Verified answer
Bonjour
Pour développer on commence par les termes entre parenthèses soit
3(x-5)(x+1) = 3( x² + x - 5x - 5) = 3( x² - 4x - 5) = 3x² - 12x - 15
Bon courage et bonne journée
0 votes
Thanks 1
maudmarine
Verified answer
Développer
:
3 (x - 5) (x + 1)
= 3 (x² + x - 5x - 5)
= 3 (x² - 4x - 5)
= 3x² - 12x - 15
1 votes
Thanks 1
hdih
envisage tu d'aller aux douze coups de midi?
hdih
mdrrr peux tu m'aider pour un autre exercice stp
hdih
peux tu m'aider pour un autre exercice stp? Merci
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Lista de comentários
Verified answer
BonjourPour développer on commence par les termes entre parenthèses soit
3(x-5)(x+1) = 3( x² + x - 5x - 5) = 3( x² - 4x - 5) = 3x² - 12x - 15
Bon courage et bonne journée
Verified answer
Développer :3 (x - 5) (x + 1)
= 3 (x² + x - 5x - 5)
= 3 (x² - 4x - 5)
= 3x² - 12x - 15