Bonjour, je dois factoriser les expressions suivantes :
(a−2)²−(a+9)²
(2x−9)²−16
(3x−3)(3x−5)+9x²−18x+9
(6x−7)(4x+2)+16x²+16x+4
(−6x−8)(5x−8)−(−6x−8)(7x+5)
(4x−7)(3x−5)+9x²−25
(a−2)²−(a+9)²
(2x−9)²−16
(3x−3)(3x−5)+9x²−18x+9
(6x−7)(4x+2)+16x²+16x+4
(−6x−8)(5x−8)−(−6x−8)(7x+5)
(4x−7)(3x−5)+9x²−25
Lista de comentários
Bonjour,
(a-2)²-(a+9)² = [(a-2)+(a+9)][(a-2)-(a+9)] car a²-b² = (a+b)(a-b)
= (2a+7)(-11)
(2x-9)²-16 = (2x-9)²-4²
= (2x-9+4)(2x-9-4)
= (2x-5)(2x-13)
(3x-3)(3x-5)+9x²-18x+9 = (3x-3)(3x-5)+(3x-3)²
= (3x-3)(3x-5)+(3x-3)(3x-3)
= (3x-3)[(3x-5)+(3x-3)]
= (3x-3)(6x-8)
= 2(3x-3)(3x-4)
(6x-7)(4x+2)+16x²+16x+4 = (6x-7)(4x+2)+(4x+2)²
= (6x-7)(4x+2)+(4x+2)(4x+2)
= (4x+2)[(6x-7)+(4x+2)]
= (4x+2)(10x-5)
= 2(2x+1)5(2x-1)
= 10(2x+1)(2x-1)
(-6x-8)(5x-8)-(-6x-8)(7x+5) = (-6x-8)[(5x-8)-(7x+5)]
= (-6x-8)(-2x-13)
= -2(3x+4)(-2x-13)
= 2(3x+4)(2x+13)
(4x-7)(3x-5)+9x²-25 = (4x-7)(3x-5)+(3x)²-5²
= (4x-7)(3x-5)+(3x+5)(3x-5)
= (3x-5)[(4x-7)+(3x+5)]
= (3x-5)(7x-2)