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DarkStar29
@DarkStar29
April 2019
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Bonjour je dois résoudre ce système par substitution
a) x + 2y = 3
3x + 4y = 5
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maudmarine
Verified answer
x + 2y = 3
3x + 4y = 5
x = 3 - 2y
3(3 - 2y) + 4y = 5
9 - 6y + 4y = 5
- 6y + 4y = 5 - 9
- 2y = - 4
y = 4/2
y = 2
x + 2y = 3
x + 2(2) = 3
x + 4 = 3
x = 3 - 4
x = - 1
Les solutions du système sont : (- 1 ; 2)
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DarkStar29
ah merci mais il faut trouver la même solution pour les deux.
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Lista de comentários
Verified answer
x + 2y = 33x + 4y = 5
x = 3 - 2y
3(3 - 2y) + 4y = 5
9 - 6y + 4y = 5
- 6y + 4y = 5 - 9
- 2y = - 4
y = 4/2
y = 2
x + 2y = 3
x + 2(2) = 3
x + 4 = 3
x = 3 - 4
x = - 1
Les solutions du système sont : (- 1 ; 2)