Réponse:
2(3-x)(2-3x)<0
<=>(6-2x)(2-3x)<0
<=>12-18x-4x+6(x^2)<0
<=>6x^2-22x+12
D=b^2 - 4×a×c
=196
X1=(22+14)÷12
=3
X2=(22-14)÷12
=2/3
S=]-oo;2/3[U]3;+oo[
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Réponse:
2(3-x)(2-3x)<0
<=>(6-2x)(2-3x)<0
<=>12-18x-4x+6(x^2)<0
<=>6x^2-22x+12
D=b^2 - 4×a×c
=196
X1=(22+14)÷12
=3
X2=(22-14)÷12
=2/3
S=]-oo;2/3[U]3;+oo[