bonjour,
soit E = (2x+1)² -4
1) E =(2x+1)² -4
E = 4x² + 4x +1 -4
E = 4x² +4x -3
2) E = (2x+1)² -4
E = ( 2x+1 +2 ) ( 2x+1 -2)
E = ( 2x+3) ( 2x -1)
3) E = ( 2x+3) ( 2x -1) = 0
D'ou deux solutions : 2x+3 = 0 et 2x-1 = 0
2x = -3 2x = 1
x = -3 /2 x = 1/2
4) si x = -3/2 alors 2x+3 = 0 donc E = 0
si x = 0 alors E = ( 3 ) (-1) = -3
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bonjour,
soit E = (2x+1)² -4
1) E =(2x+1)² -4
E = 4x² + 4x +1 -4
E = 4x² +4x -3
2) E = (2x+1)² -4
E = ( 2x+1 +2 ) ( 2x+1 -2)
E = ( 2x+3) ( 2x -1)
3) E = ( 2x+3) ( 2x -1) = 0
D'ou deux solutions : 2x+3 = 0 et 2x-1 = 0
2x = -3 2x = 1
x = -3 /2 x = 1/2
4) si x = -3/2 alors 2x+3 = 0 donc E = 0
si x = 0 alors E = ( 3 ) (-1) = -3