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Alexiadevoirs
@Alexiadevoirs
January 2021
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Bonjour je n'arrive pas à mon exercice 2 sur le théorème de Pythagore l'exercice est en pièce jointe. j'aimerais que les réponses soient détaillés merci (:
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xelette34
Abcd rectangle donc DA = CB et DC = AB
1/ Th de Pythagore
DE² = DA²+AE² = 2.4²+1² = 6.76
Racine carré 6.76 = DE = 2.6
2/ ECB rectangle en B Th de P
EC² = EB²+CB²
4²-EB² + 2.4²
EB² = 16-5.76 = 10.24
Racine 10.24 = EB = 3.2
AB = 3.2+1 = 4.2
Reciproque de P pour savoir si tr rect
DC² = 4.2²=17.64
DE²+EC² = 2.6²+4²=22.76
Donc non pas triangle rectangle
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Alexiadevoirs
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Bonjour, j'aimerais savoir cela fait combien: (-8) + (-4) (-7) x (-3) (+18) : (-6) (+7)-(+5) ; 5 x (-2) ; - 8 - 9 ; -16 : 4 ; -4 x (-5) ; (-2) x (-5) x (+1) x (-3) x (+2) ; (-2) + (-5) + (+1) + (-3) + (+2) ; -3 + 4 x 8 ; 7 + 6 x (-2) ; (-200-70) : (-30) ; -10 + 4 x 4 ; 38- 5 x 5 ; - (-9) - 5 x 3 +4
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Lista de comentários
1/ Th de Pythagore
DE² = DA²+AE² = 2.4²+1² = 6.76
Racine carré 6.76 = DE = 2.6
2/ ECB rectangle en B Th de P
EC² = EB²+CB²
4²-EB² + 2.4²
EB² = 16-5.76 = 10.24
Racine 10.24 = EB = 3.2
AB = 3.2+1 = 4.2
Reciproque de P pour savoir si tr rect
DC² = 4.2²=17.64
DE²+EC² = 2.6²+4²=22.76
Donc non pas triangle rectangle