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Nightmarish
@Nightmarish
May 2019
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Bonjour ! Je n'arrive pas à résoudre cet exercice donc un peu d'aide ne serait pas de refus.
merci d'avance !
la question est: indiquer le sens de variation des fonctions affines données
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trudelmichel
Bonjour,
g(x)=(2-x)/2+(1/2)x
g(x)= [(2-x)+(x)]/2
g(x)= (2-x+x)/2
g(x)=2/2
g(x)=1
g(x) n'est pas une fonction affine
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g(x)=(2-x)/2+(1/2)x
g(x)= [(2-x)+(x)]/2
g(x)= (2-x+x)/2
g(x)=2/2
g(x)=1
g(x) n'est pas une fonction affine