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chloe1912
@chloe1912
January 2021
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bonjour
je n’arrive pas a resoudre cet exercice
quelqu’un pourrait m’aider ?
si vous pourriez montrer les etapes ce serair super
merci bien !!
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elodiecasanovap7bwfo
1°) Si x =2 alors A= 14x2-5x2(4-2x2)=28-10x0=28
Si x=-3 alors A= 14x(-3)-5x(-3)(4-2x(-3))=-42+15x10=-42+150=108
2°) A=14x-5x(4-2x)=14x-5x*4+5x*2x=14x-20x+10x^2=10x^2-6x
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Si x=-3 alors A= 14x(-3)-5x(-3)(4-2x(-3))=-42+15x10=-42+150=108
2°) A=14x-5x(4-2x)=14x-5x*4+5x*2x=14x-20x+10x^2=10x^2-6x