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marieep
@marieep
January 2021
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Bonjour je n'arrive pas à résoudre cette équation pouvez vous m'aidez svp
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Ramsses
Bonjour,
x + 1 ≠ 0
x ≠ -1
2 - (8-x)/(x+1) = 0
(2x + 2)/(x + 1) - (8-x)/(x+1) = 0
(2x + 2 - 8 + x)/(x+1) = 0
(3x - 6)/(x+1) = 0
3(x - 2) /(x + 1) = 0/(x + 1)
3(x - 2) = 0
x - 2 = 0 ou 3 = 0
x = 2 x = 0
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marieep
merci
supersong
Verified answer
X+1≠0 donc x≠-1
on met tout au meme denominateur on aura donc [2(x+1)-(8-x)]:x+1=0
⇒ 2x+2-8+x=0 ⇒3x-6=0 ⇒x=2
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Thanks 0
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Lista de comentários
x + 1 ≠ 0
x ≠ -1
2 - (8-x)/(x+1) = 0
(2x + 2)/(x + 1) - (8-x)/(x+1) = 0
(2x + 2 - 8 + x)/(x+1) = 0
(3x - 6)/(x+1) = 0
3(x - 2) /(x + 1) = 0/(x + 1)
3(x - 2) = 0
x - 2 = 0 ou 3 = 0
x = 2 x = 0
Verified answer
X+1≠0 donc x≠-1on met tout au meme denominateur on aura donc [2(x+1)-(8-x)]:x+1=0
⇒ 2x+2-8+x=0 ⇒3x-6=0 ⇒x=2