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romarickmlk
@romarickmlk
May 2022
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Bonjour je ne comprend pas cette exercice quelqu’un pour m’aider , m’expliquer svp
merci d’avance ! :))
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Bernie76
Réponse :BonjourExplications étape par étape :Voir dessin joint.cos ^BAC=AB/AC=16.5/25=0.66^BAC ≈ 48.7°Pythagore dans ABC rectangle en B :AC²=BA²+BC²25²=16.5²+BC²BC²=25²-16.5²=352.75BC ≈ 18.78 mBE=18.78+7.32=26.1Dans triangle ABE rectangle en B :tan BAE=BE/BA=26.1/16.5≈1.58^BAE ≈ 57.7 °^CAE =57.7-48.7^CAE ≈ 9°
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Thanks 1
romarickmlk
Merci beaucoup de m’avoir expliqué ! :)
Bernie76
: - )
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