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Esma57
@Esma57
May 2019
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Bonjour je suis bloquer sur mon exo de maths vous pouvez m’aider svp, merci d’avance
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aymanemaysae
Bonjour ;
Soit "d" le diamètre du cylindre ;
donc son volume est : π x (d/2)² x d = π/4 x d^3 = 720 mm^3 ;
donc : π d^3 = 4 x 720 =2880 mm^3 .
Le volume de la boule est :
4/3 x π x (d/2)^3 = 4/3 x π x (d^3)/8 = 1/6 x π d^3
= 1/6 x 2880 = 480 mm^3 .
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Vous pouvez m aider pour mes exos de maths svp mrc d avance .
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Soit "d" le diamètre du cylindre ;
donc son volume est : π x (d/2)² x d = π/4 x d^3 = 720 mm^3 ;
donc : π d^3 = 4 x 720 =2880 mm^3 .
Le volume de la boule est :
4/3 x π x (d/2)^3 = 4/3 x π x (d^3)/8 = 1/6 x π d^3
= 1/6 x 2880 = 480 mm^3 .