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Macana
@Macana
May 2019
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Bonjour je suis en 3ème et j'ai besoin d'aide pour un exo le voici
f est un fonction affine telle que f(3)=10 et f(1)=6. Quelle est son expression algébrique ?
merci par avance de votre aide
ps: je n'ai que ça comme énoncer
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Bonjour,
fonction affine = ax+b
f(3)=10⇒3a+b = 10
f(1)=6⇒a+b = 6
3a+b = 10
a+b = 6
-1(3a+b) = 10
a+b = 6
-3a-b =-10
a+b = 6
-2a = -4
a = 2
a+b = 6
2+b = 6
b = 6-2
= 4
f(x) = 2x+4
3 votes
Thanks 1
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Bonjour,fonction affine = ax+b
f(3)=10⇒3a+b = 10
f(1)=6⇒a+b = 6
3a+b = 10
a+b = 6
-1(3a+b) = 10
a+b = 6
-3a-b =-10
a+b = 6
-2a = -4
a = 2
a+b = 6
2+b = 6
b = 6-2
= 4
f(x) = 2x+4