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HeraniXX
@HeraniXX
May 2019
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Bonjour je suis en train de faire mon dm sur la factorisation et voici le seul ex que je ne comprend pas pouvez vous m'aider
Merci
(2x - 8)² - (x-3)²
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Commentaires (1)
Il faut utiliser la 3e identité remarquable : a² - b² = (a+b)(a-b)
avec a = 2x-8 et b = x-3
ainsi :
(2x-8)² - (x-3)² = [(2x-8)+(x-3)][(2x-8)-(x-3)]
= (2x+x-8-3)(2x-x-8+3)
= (3x-11)(x-5)
3 votes
Thanks 1
HeraniXX
Merci j'aicompris ce que tu voulais dire
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avec a = 2x-8 et b = x-3
ainsi :
(2x-8)² - (x-3)² = [(2x-8)+(x-3)][(2x-8)-(x-3)]
= (2x+x-8-3)(2x-x-8+3)
= (3x-11)(x-5)