Verified answer

Explications:

M(C12H22O11) = 12×M(C)+22×M(H)+11×M(O)

= 12×12+22+11×16

= 124+22+176

= 322 g/mol

6/322 = 0.02 mol de saccharose dans le sucre

0.02/0.25=0.08 L

0.08 L de saccharose dans un morceau de sucre

0.25 mol -> 1

0.0825 mol -> 33 ×10^-2

0.0825/0.08 = 1,03 sucres