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January 2021
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Bonjour, merci de répondre
Déveloper : (1-x) au carré - (4x+7) au carré
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Anna1712
Bonjour,
(1-X)^2 - (4X + 7)^2 = 1^2 - 2x1xX + X^2 - (4X^2 + 2x4Xx7 + 7^2)
= 1 - 2X + X^2 - (4X^2 + 56X + 49)
= X^2 - 4X^2 - 2X - 56X + 1 - 49
= - 3X^2 - 58X - 48
Voilà, j'espère ne pas m'être trompée ^^' (^2 signifie "au carré")
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vert
Merci beaucoup mais je pense que tu as fait une erreur de signee
Anna1712
A quel endroit ?
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(1-X)^2 - (4X + 7)^2 = 1^2 - 2x1xX + X^2 - (4X^2 + 2x4Xx7 + 7^2)
= 1 - 2X + X^2 - (4X^2 + 56X + 49)
= X^2 - 4X^2 - 2X - 56X + 1 - 49
= - 3X^2 - 58X - 48
Voilà, j'espère ne pas m'être trompée ^^' (^2 signifie "au carré")