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lisaam
@lisaam
January 2021
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Bonjour (niveau 3ème)
Est ce que quelqu'un pourrait m'aider à cette exercice ? Merci d'avance.
La consigne est : Calcule rapidement en utilisant une identité remarquable.
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emi1903
Tu sais se que c'est une identité remarquable?
0 votes
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simoraina619
Bonjour, voila la reponse
c. (100-1)²
= (100)² -2(100)(1) + 1²
= 10000 -200 +1
= 9801
d.401×399 = (400-1)(400+1)
= (400)² -1²
= 159999
e. 45×35 = (40-5)(40+5)
= 40² -5²
= 1575
1 votes
Thanks 1
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Lista de comentários
c. (100-1)²
= (100)² -2(100)(1) + 1²
= 10000 -200 +1
= 9801
d.401×399 = (400-1)(400+1)
= (400)² -1²
= 159999
e. 45×35 = (40-5)(40+5)
= 40² -5²
= 1575