Bonjour :)
a = 2^(3^4) or 3^4 = 81
donc a = 2^81 ≈ 2,4 x 10^24
b = 3^(4^2) or 4^2 = 16
donc b = 3^16 ≈ 4,3 x 10^7
c = 4^(2^3) or 2^3 = 8
donc c = 4^8 ≈ 6,6 x 10^4
On a donc c<b<a :)
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Bonjour :)
a = 2^(3^4) or 3^4 = 81
donc a = 2^81 ≈ 2,4 x 10^24
b = 3^(4^2) or 4^2 = 16
donc b = 3^16 ≈ 4,3 x 10^7
c = 4^(2^3) or 2^3 = 8
donc c = 4^8 ≈ 6,6 x 10^4
On a donc c<b<a :)