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zoeguerard
@zoeguerard
May 2022
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Bonjour, pourriez-vous m’aider pour cet exercice, s’il vous plaît
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taalbabachir
Réponse :D(3 ; y)vec(AB) = (7 ; 3)vec(CD) = (4 ; y+2)dét(AB ; CD) = XY' - X'Y = 0 ⇔ 7(y+2) - 12 = 0 ⇔ 7 y + 14 +12 = 07y = - 26 ⇔ y = - 26/7 Explications étape par étape :
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zoeguerard
Merci beaucoup
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