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magalivinet
@magalivinet
January 2021
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bonjour pourriez vous m'aider pour mon exercice de maths je suis en troisième s'il vous plait merci d'avance
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rosiemuller2000
Verified answer
Coucou
a) CT/MW = PC/PM = PT/PW
CT/3,40 = 3,78/4,20 = PT/PW
CT = (3,40*3,78)/4,2 = 3,06
3,06 * 2= 6,12
La quantité de fil necessaire est 6,12 m
b)
CT/3,4 = 1,88/2,3
CT = (3,4*1,88)/2,3 ≈ 2,779
2,779 ≠ 3,06 donc d'apres la contraposée du theoreme de thales CT nest pas // a MW
voila j espere t avoir aider
1 votes
Thanks 1
magalivinet
oh oui merci pour tout
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Verified answer
Coucoua) CT/MW = PC/PM = PT/PW
CT/3,40 = 3,78/4,20 = PT/PW
CT = (3,40*3,78)/4,2 = 3,06
3,06 * 2= 6,12
La quantité de fil necessaire est 6,12 m
b)
CT/3,4 = 1,88/2,3
CT = (3,4*1,88)/2,3 ≈ 2,779
2,779 ≠ 3,06 donc d'apres la contraposée du theoreme de thales CT nest pas // a MW
voila j espere t avoir aider