Réponse:
par theoreme de thalus
Explications étape par étape:
ona (MN)//(BC)
c a d AN/AC=AM/AB=MN/BC=4/6
AM/AB=MN/BC=4/6
x/AB =4/6
x =(AM+MB)4/6
x =(4/6×) +4/6MB
x_4/6x = 4/6 MB
( 1_4/6)x =4/6×3
2/6 x =4/2
1/3x =2
x = 6
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Réponse:
par theoreme de thalus
Explications étape par étape:
ona (MN)//(BC)
c a d AN/AC=AM/AB=MN/BC=4/6
AM/AB=MN/BC=4/6
x/AB =4/6
x =(AM+MB)4/6
x =(4/6×) +4/6MB
x_4/6x = 4/6 MB
( 1_4/6)x =4/6×3
2/6 x =4/2
1/3x =2
x = 6