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Eleve86
@Eleve86
May 2019
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Bonjour, pourriez vous m'aidez j'ai du mal avec la factorisation
Factorise les expressions suivantes : Y (3 x+1)(−2 x+3)−(3 x+1)(5−2 x )
D=(x+3)(2 x+2)−(x+3)( x−1)
E=4 x 2−9+(2 x−3)(x+5)
merci d'avance^^
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mathador37
Verified answer
(3 x+1)(−2 x+3)−(3 x+1)(5−2 x )
=
(3 x+1)[(−2 x+3)-(5−2 x )]
=(3 x+1)[−2 x+3-5+2 x]
=(3 x+1)[3-5]
=-2(3x+1)
D=(x+3)(2 x+2)−(x+3)( x−1)
D=(x+3)[(2 x+2)−( x−1)]
D=(x+3)[2 x+2−x+1)]
D=(x+3)(x+3)
E=4 x 2−9+(2 x−3)(x+5)
E=(2x+3)(2x-3)+(2 x−3)(x+5)
E=(2x-3)[(2x+3)+(x+5)]
E=(2x-3)[3x+8]
A bientôt!
mathador
"ne prenez pas de risque : calculez le!!"
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Verified answer
(3 x+1)(−2 x+3)−(3 x+1)(5−2 x )= (3 x+1)[(−2 x+3)-(5−2 x )]
=(3 x+1)[−2 x+3-5+2 x]
=(3 x+1)[3-5]
=-2(3x+1)
D=(x+3)(2 x+2)−(x+3)( x−1)
D=(x+3)[(2 x+2)−( x−1)]
D=(x+3)[2 x+2−x+1)]
D=(x+3)(x+3)
E=4 x 2−9+(2 x−3)(x+5)
E=(2x+3)(2x-3)+(2 x−3)(x+5)
E=(2x-3)[(2x+3)+(x+5)]
E=(2x-3)[3x+8]
A bientôt!
mathador
"ne prenez pas de risque : calculez le!!"