bonjour
f (x) = - 2 x
- 2 x = 2
x = - 1 → f (-1) = 2
- 2 x = 0
x = 0 → f (0) = 0
f (x) = 5 x + 1
5 x + 1 = - 1
5 x = - 1 - 1
5 x = - 2
x = - 2/5 → f ( - 2/5) = - 1
5 x + 1 = 0
5 x = - 1
x = - 1/5 → f ( - 1/5) = 0
f (x) = 2 x² + 1
2 x ² + 1 = 2
2 x² = 2 - 1
2 x² = 1
x² = 1/2
x = √ 1/2 ou - √ 1/2 → f ( √1/2) = 2 et f ( - √1/2) = 2
2 x² + 1 = 0
2 x² = - 1 → pas de solution dans R
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bonjour
f (x) = - 2 x
- 2 x = 2
x = - 1 → f (-1) = 2
- 2 x = 0
x = 0 → f (0) = 0
f (x) = 5 x + 1
5 x + 1 = - 1
5 x = - 1 - 1
5 x = - 2
x = - 2/5 → f ( - 2/5) = - 1
5 x + 1 = 0
5 x = - 1
x = - 1/5 → f ( - 1/5) = 0
f (x) = 2 x² + 1
2 x ² + 1 = 2
2 x² = 2 - 1
2 x² = 1
x² = 1/2
x = √ 1/2 ou - √ 1/2 → f ( √1/2) = 2 et f ( - √1/2) = 2
2 x² + 1 = 0
2 x² = - 1 → pas de solution dans R