Bonjour,
1) V = π × (5/2)² × 16 ÷ 3 = 100π/3 cm³ ≅ 104,7 cm³
2) a) coefficient de réductiion = SO'/SO = 12/16 = 0,75
donc V₁ = V × 0,75³ = 100π/3 × 0,75³
= 42,1875π/3
≅ 44,2 cm³
3) V₂ = V - V₁ = 100π/3 - 42,1875π/3
= 57,8125π/3
≅ 60,5 cm³
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Bonjour,
1) V = π × (5/2)² × 16 ÷ 3 = 100π/3 cm³ ≅ 104,7 cm³
2) a) coefficient de réductiion = SO'/SO = 12/16 = 0,75
donc V₁ = V × 0,75³ = 100π/3 × 0,75³
= 42,1875π/3
≅ 44,2 cm³
3) V₂ = V - V₁ = 100π/3 - 42,1875π/3
= 57,8125π/3
≅ 60,5 cm³