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Colline14
@Colline14
May 2019
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Bonjour, pourriez-vous me dire ce qui n'est pas correct?
Il s'agit de calculs pour trouver l'équation de la tangente
C'est très très urgent je ne comprends pas
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anylor
Bonjour
formule du cours
y = f(a) + f '(a) (x- a)
f(a) =3a²-a+1
f '(a) = 6x -1
l'énoncé donne a = 1
donc f(1) = 3×1 - 1 +1 = 3
f '(1) = 6×1 -1 = 5
on applique la formule :
y = 3 + 5 (x -1)
y = 3 +5x -5
y = 5x - 2
si tu as des question n'hésite pas
1 votes
Thanks 1
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formule du cours
y = f(a) + f '(a) (x- a)
f(a) =3a²-a+1
f '(a) = 6x -1
l'énoncé donne a = 1
donc f(1) = 3×1 - 1 +1 = 3
f '(1) = 6×1 -1 = 5
on applique la formule :
y = 3 + 5 (x -1)
y = 3 +5x -5
y = 5x - 2
si tu as des question n'hésite pas