Bonjour. Pourriez vous m'expliquer un calcul corrigé? ( cest pressé)
D)=(3x+1)²+(x+5)(3x+1)
=(3x+1)(3x+1)+(x+5)(3x+1)      là je comprends.
=(3x+1)[3x+1)+(x+5)]                là,pourquoi retirons-nous une foix (3x+1)????
=(3x+1)[3x+1+x+5]
=(3x+1)(4x+6)
merci d'avance
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