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Eliina01
@Eliina01
May 2019
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Bonjour, Pourriez vous m'expliquez comment développer cette équation: (4x+3y+2)²=0
Merci
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maudmarine
Verified answer
Bonjour,
(4x+3y+2)²=0
(4x + 3y + 2) (4x + 3y + 2) = 0
16x² + 12xy + 8x + 12xy + 9y² + 6y + 8x + 6y + 4 = 0
16x²+ 9y² + 12xy + 12xy + 8x + 8x + 6y + 6y + 4 = 0
16x² + 9y² + 24xy + 16x + 12y + 4 = 0
1 votes
Thanks 1
Eliina01
Merci pour ta réponse !
maudmarine
Je ne vois pas ce que ça peut être d'autre...
Eliina01
Moi non plus, t'inquiète pas c'est très bien
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Lista de comentários
Verified answer
Bonjour,(4x+3y+2)²=0
(4x + 3y + 2) (4x + 3y + 2) = 0
16x² + 12xy + 8x + 12xy + 9y² + 6y + 8x + 6y + 4 = 0
16x²+ 9y² + 12xy + 12xy + 8x + 8x + 6y + 6y + 4 = 0
16x² + 9y² + 24xy + 16x + 12y + 4 = 0