bonjour
on doit passer de "merci de manger et merci de boire"
à "merci de manger et boire"
trouver le facteur commun pour passer de k*a + k*b à k (a+b)
a) 3x + 9 = 3 * x + 3 * 3 = 3 (x+3)
b) 4x – x2 = x * 4 - x * x = x (4 - x)
c)(x+4)(x–1) +2(x+4) = (x+4) [(x-1+2] = (x+4) (x+1)
d) (2x – 3)(x + 5) + (x – 6)(2x – 3)
= (2x-3) [(x+5) + (x-6)] = (2x-3) (2x-1)
e) (4x – 5)(x – 3) – (x – 3)(x-3)
= (x-3) (3x-2)
Bonjour;
a) 3x + 9
=3( x=3)
b) 4x – x²
= x(4 -x)
c)(x+4)(x–1) +2(x+4)
(x+4) (x-1 +2)
=(x+4) x +1)
= (2x-3) ( x+5 +x-6)
= (2x-3) ( 2x -1)
e) (4x – 5)(x – 3) – (x – 3)²
=(x-3) ( 4x-5 -x +3)
= (x-3) ( 3x -2)
=
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
bonjour
on doit passer de "merci de manger et merci de boire"
à "merci de manger et boire"
trouver le facteur commun pour passer de k*a + k*b à k (a+b)
a) 3x + 9 = 3 * x + 3 * 3 = 3 (x+3)
b) 4x – x2 = x * 4 - x * x = x (4 - x)
c)(x+4)(x–1) +2(x+4) = (x+4) [(x-1+2] = (x+4) (x+1)
d) (2x – 3)(x + 5) + (x – 6)(2x – 3)
= (2x-3) [(x+5) + (x-6)] = (2x-3) (2x-1)
e) (4x – 5)(x – 3) – (x – 3)(x-3)
= (x-3) (3x-2)
Verified answer
Bonjour;
a) 3x + 9
=3( x=3)
b) 4x – x²
= x(4 -x)
c)(x+4)(x–1) +2(x+4)
(x+4) (x-1 +2)
=(x+4) x +1)
d) (2x – 3)(x + 5) + (x – 6)(2x – 3)
= (2x-3) ( x+5 +x-6)
= (2x-3) ( 2x -1)
e) (4x – 5)(x – 3) – (x – 3)²
=(x-3) ( 4x-5 -x +3)
= (x-3) ( 3x -2)
=