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Clac
@Clac
April 2019
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Bonjour, pouvez-vous m aider à résoudre une factorisation s'il vous plait
h (x)= ( ×-1)(2×-3)-(1-×)2 + ×-1
i (×)=(2×+3)(×-1)+(×+1)(4-5×)
merci d avance:)
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anylor
1)
h (x)= ( x-1)(2x-3)-(1-x)² + x-1
on met x-1 en facteur
sachant que -( 1-x) ² = -(x-1)²
(x-1) [ 2x -3 – x +1 +1]
= (x-1) ( x -1)
h(x) = (x-1)²
2)
i (x)= (2x+3)(x-1)+(x+1)(4-5x)
on développe
=2x² -2x +3x -3 +4x -5x² +4 - 5x
= -3x² +1 identité remarquable (a²-b²)
= ( 1 - √3x) ( 1+√3x)
es tu sure de ton énoncé ?
si
i (x)= (2x+3)(x-1)+(x-1)(4-5x)
i(x) = (x-1) ( 7-3x)
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Lista de comentários
h (x)= ( x-1)(2x-3)-(1-x)² + x-1
on met x-1 en facteur
sachant que -( 1-x) ² = -(x-1)²
(x-1) [ 2x -3 – x +1 +1]
= (x-1) ( x -1)
h(x) = (x-1)²
2)
i (x)= (2x+3)(x-1)+(x+1)(4-5x)
on développe
=2x² -2x +3x -3 +4x -5x² +4 - 5x
= -3x² +1 identité remarquable (a²-b²)
= ( 1 - √3x) ( 1+√3x)
es tu sure de ton énoncé ?
si
i (x)= (2x+3)(x-1)+(x-1)(4-5x)
i(x) = (x-1) ( 7-3x)