Articles
Register
Sign In
Search
matth15
@matth15
January 2021
1
93
Report
Bonjour pouvez vous m aider sur cet exercice merci
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
maudmarine
Verified answer
Bonjour,
Quel est le nombre total de cubes dont je dispose
?
Soient x le nombre de cubes de 3 cm et y le nombre de cubes de 7 cm
x * 3³ + y * 7³ = 10 000 cm³ (volume)
et
3x + 7y = 520 cm (longueurs)
On a donc :
27x + 343y = 10 000
3x + 7y = 520
27x + 343y = 10 000
27x + 63y = 4680
280y = 5320
y = 5320/280
y = 19
27x + 63y = 4680
27x + 63 * 19 = 4680
27x + 1197 = 4680
27x = 4680 - 1197
27x = 3483
x = 3483/27
x = 129
Je dispose de 129 cubes de 3 cm et de 19 cubes de 7 cm.
1 votes
Thanks 1
More Questions From This User
See All
matth15
January 2021 | 0 Respostas
Responda
matth15
January 2021 | 0 Respostas
Responda
Matth15
January 2020 | 0 Respostas
Responda
Matth15
January 2020 | 0 Respostas
Me expliquem o que e blendings?
Responda
Matth15
December 2019 | 0 Respostas
O que significa SML na linguagem das meninas ?
Responda
Matth15
December 2019 | 0 Respostas
Responda
Matth15
May 2019 | 0 Respostas
Pouvez vous m aider sur cette exercice ? svp merci
Responda
Matth15
May 2019 | 0 Respostas
Responda
Matth15
May 2019 | 0 Respostas
Responda
Matth15
May 2019 | 0 Respostas
Responda
×
Report "Bonjour pouvez vous m aider sur cet exercice merci.... Pergunta de ideia de matth15"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjour,Quel est le nombre total de cubes dont je dispose ?
Soient x le nombre de cubes de 3 cm et y le nombre de cubes de 7 cm
x * 3³ + y * 7³ = 10 000 cm³ (volume)
et
3x + 7y = 520 cm (longueurs)
On a donc :
27x + 343y = 10 000
3x + 7y = 520
27x + 343y = 10 000
27x + 63y = 4680
280y = 5320
y = 5320/280
y = 19
27x + 63y = 4680
27x + 63 * 19 = 4680
27x + 1197 = 4680
27x = 4680 - 1197
27x = 3483
x = 3483/27
x = 129
Je dispose de 129 cubes de 3 cm et de 19 cubes de 7 cm.