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Honorinlauriane
@Honorinlauriane
January 2021
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bonjour pouvez vous m aider svp
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nguyenso9
Verified answer
Bonjour,
AH = AB - HB = 35 - 1,8 = 33,2 m
D'apres le theoreme de Pythagore,
AD² = AH² + HD²
HD² = AD² - AH²
= 80² - 33,2²
= 5 297,76
HD = √5297,76
HD ≈ 72,8 m
La disance entre l'eolienne est l'homme est d'environ 72,8 m
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Verified answer
Bonjour,AH = AB - HB = 35 - 1,8 = 33,2 m
D'apres le theoreme de Pythagore,
AD² = AH² + HD²
HD² = AD² - AH²
= 80² - 33,2²
= 5 297,76
HD = √5297,76
HD ≈ 72,8 m
La disance entre l'eolienne est l'homme est d'environ 72,8 m