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quines1
@quines1
June 2021
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BONjour pouvez vous m aidez a resoudre cette inequations
(4x + 3)² - 4 suprerieur ou egale a 0
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Omnes
Salut,
(x+3)² - 4 ≥ 0
(x+3)² - 2² ≥ 0
(x+3+2)(x+3-2) ≥ 0
(x+5)(x+1) ≥ 0
x + 5 ≥ 0
x ≥ - 5
x + 1 ≥ 0
x ≥ -1
Bonne soirée !
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Thanks 1
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aidez MOI S IL VOUS PLAIT C EST URGENT :(
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(x+3)² - 4 ≥ 0
(x+3)² - 2² ≥ 0
(x+3+2)(x+3-2) ≥ 0
(x+5)(x+1) ≥ 0
x + 5 ≥ 0
x ≥ - 5
x + 1 ≥ 0
x ≥ -1
Bonne soirée !