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Mtibtt
@Mtibtt
January 2021
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Bonjour pouvez vous m'aider à calculer les antécédents de 0 et -16 par le fonction
(3x-2)²-16
Merci
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AhYan
Bonsoir,
(3x-2)² - 16 = 0 ==> une identité remarquable
(3x-2)² - 4² = 0
(3x-2-4)(3x-2+4) = 0
(3x-6)(3x+2) = 0 ==> une équation produit nul
donc on a :
soit 3x-6 = 0 <=> 3x = 6 <=> x = 6/3 <=> x = 2
soit 3x+2 = 0 <=> 3x = -2 <=> x = -⅔
(3x-2)² - 16 = -16
(3x-2)² = -16+16
(3x-2)² = 0
3x-2 = 0
3x = 2
x = ⅔
2 votes
Thanks 0
Mtibtt
Merci beaucoup
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(3x-2)² - 16 = 0 ==> une identité remarquable
(3x-2)² - 4² = 0
(3x-2-4)(3x-2+4) = 0
(3x-6)(3x+2) = 0 ==> une équation produit nul
donc on a :
soit 3x-6 = 0 <=> 3x = 6 <=> x = 6/3 <=> x = 2
soit 3x+2 = 0 <=> 3x = -2 <=> x = -⅔
(3x-2)² - 16 = -16
(3x-2)² = -16+16
(3x-2)² = 0
3x-2 = 0
3x = 2
x = ⅔