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Anais1729
@Anais1729
May 2019
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Bonjour pouvez vous m'aider à faire cet exercice? Merci d'avance
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F(x)=(x+1)(x+4)
1)a) f(x)=x²+x+4x-4=x²+5x+4
b) f(x)=x²+5x+6,25-6,25+4
=(x+2,5)²-2,25
2)a) f(x)<0
(x+1)(x+4)<0
-1<x<-4
b) f(x>x²-1
x²+5x+4>x²-1
5x>-5
x>-1
c) f(x)>-9/4
(x+2,5)²-2,25>-9/4
(x+2,5)²>0
tout réel x≠-2,5 est solution
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1)a) f(x)=x²+x+4x-4=x²+5x+4
b) f(x)=x²+5x+6,25-6,25+4
=(x+2,5)²-2,25
2)a) f(x)<0
(x+1)(x+4)<0
-1<x<-4
b) f(x>x²-1
x²+5x+4>x²-1
5x>-5
x>-1
c) f(x)>-9/4
(x+2,5)²-2,25>-9/4
(x+2,5)²>0
tout réel x≠-2,5 est solution