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Vouriampa
@Vouriampa
May 2019
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Bonjour pouvez vous m'aider à faire ses factorisation s'il vous plaît merci
Factoriser si possible les expressions suivantes :
E = (2t+1)^2-(t+1)^2
F = (3t-7)^2- 25
G = (3t+4)^2-(2t+3)^2
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no63
Salut
E=(2t+1)^2-(t+11)^2 => A^2-B^2 =>(a-b)(a+b)
E=(2t+1-t-1)(2t+1+t+1)
E=t (3t+2)
F=(3t-7)^2-25 =>A^2-B^2 =>(a-b)(a+b)
F=(3t-7+5)(3t-7-5)
F=(3t-2)(3t-12)
G=(3t+4)^2-(2t+3)^2 =>A^2-B^2
G=(3t+4+2t+3)(3t+4-2t-3)
G=(5t+7)(t+1)
vérifies quand meme
2 votes
Thanks 1
Vouriampa
Merci
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Bjr tout le monde pouvez vous m'aider cet exercice car je ne l'ai pas compris merci d'avantage
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E=(2t+1)^2-(t+11)^2 => A^2-B^2 =>(a-b)(a+b)
E=(2t+1-t-1)(2t+1+t+1)
E=t (3t+2)
F=(3t-7)^2-25 =>A^2-B^2 =>(a-b)(a+b)
F=(3t-7+5)(3t-7-5)
F=(3t-2)(3t-12)
G=(3t+4)^2-(2t+3)^2 =>A^2-B^2
G=(3t+4+2t+3)(3t+4-2t-3)
G=(5t+7)(t+1)
vérifies quand meme