bjr
x² - 25 = (x)² - (5)² = (x+5) (x-5) puisque a² - b² = (a+b) (a-b)
(x+2) (3x-1) = x*3x + x*(-1) + 2*3x + 2*(-1) = 3x² -x + 6x - 2 = 3x² + 5x - 2
4x² + 3x = 4*x* + 3*x = x(4x+3)
28 = 2x14 = 2x2x7 = 2²x7
diagonale rectangle de 10 cm x 20 cm
diag² = 10² + 20² = 500 (pythagore)
=> diag ≈ 22 cm
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bjr
x² - 25 = (x)² - (5)² = (x+5) (x-5) puisque a² - b² = (a+b) (a-b)
(x+2) (3x-1) = x*3x + x*(-1) + 2*3x + 2*(-1) = 3x² -x + 6x - 2 = 3x² + 5x - 2
4x² + 3x = 4*x* + 3*x = x(4x+3)
28 = 2x14 = 2x2x7 = 2²x7
diagonale rectangle de 10 cm x 20 cm
diag² = 10² + 20² = 500 (pythagore)
=> diag ≈ 22 cm