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Fredericcadot
@Fredericcadot
May 2019
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Bonjour pouvez vous m'aider ? je dois Développer, reduire et factoriser C sachant que C=(4x-3)(x-1)-5(4x-3) merci
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Sulky
Bonjour,
développement :
C = (4x - 3)(x - 1) - 5(4x - 3)
C = 4x² - 4x - 3x + 3 - 20x + 15
C = 4x² - 27x + 18
factorisation :
(4x - 3)(x - 1) - 5(4x - 3)
= (4x - 3)(x - 1 - 5)
= (4x - 3)(x - 6)
2 votes
Thanks 1
fredericcadot
waoo on ne peut plus clair ! merci bcp c'est vraiement sympa je vais garder ce modèle pour la prochaine fois
fredericcadot
Bonjour pouvez vous encore m'aider ? pour 1 dernier
Sulky
avec plaisir
fredericcadot
Bonjour pouvez vous encore m'aider ? Ecrire sous forme de fraction irréductible A = -1/2 + 5/2 x (1-1/2) et B = 5/7 : 6/7-(1/2-1)
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développement :
C = (4x - 3)(x - 1) - 5(4x - 3)
C = 4x² - 4x - 3x + 3 - 20x + 15
C = 4x² - 27x + 18
factorisation :
(4x - 3)(x - 1) - 5(4x - 3)
= (4x - 3)(x - 1 - 5)
= (4x - 3)(x - 6)