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Maheemrc
@Maheemrc
May 2019
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Bonjour pouvez-vous m’aider pour cet exercice de maths (exercice 7) s’il vous plaît. Merci d’avance.
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taalbabachir
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Soit le triangle ABC rectangle en B
⇒ cos 40° = BC/AC ⇒ BC = AC x cos 40° = 10 x 0.766 = 7.66 cm = 76.6 mm
BC = 77 mm
sin 40° = AB/AC ⇒ AB = AC x sin 40° = 10 x 0.64278 = 6.4278 cm = 64.278 mm
⇒ AB = 64 mm
cos 40° = CH/BC ⇒ CH = BC x cos 40° = 7.66 x 0.766 = 5.86756 cm
⇒ AH = AC - CH = 10 - 5.86756 = 4.13244 cm = 41.3244 mm
⇒ AH = 41 mm
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Bonjour je n'arrive pas a cette exercice. merci de m'aider (a rendre pour demain)
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Verified answer
Soit le triangle ABC rectangle en B⇒ cos 40° = BC/AC ⇒ BC = AC x cos 40° = 10 x 0.766 = 7.66 cm = 76.6 mm
BC = 77 mm
sin 40° = AB/AC ⇒ AB = AC x sin 40° = 10 x 0.64278 = 6.4278 cm = 64.278 mm
⇒ AB = 64 mm
cos 40° = CH/BC ⇒ CH = BC x cos 40° = 7.66 x 0.766 = 5.86756 cm
⇒ AH = AC - CH = 10 - 5.86756 = 4.13244 cm = 41.3244 mm
⇒ AH = 41 mm