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Cyruzovato
@Cyruzovato
January 2021
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Bonjour pouvez-vous m'aider s'il vous plaît : expliquer pourquoi 9* (111 * a+ 11 * b+c) est divisible par 9
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totolekoala
Si a, b et c sont des entiers naturels, alors par définition
9* (111 * a+ 11 * b+c) est un multiple de 9, donc divisible par 9 :)
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Cyruzovato
Mercii bcp
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Aidez moi svp juste pour le "A ton Tour " merci
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