Bonjour,
1) DB = 250 + 20 = 270
Théorème de Pythagore :
ED² = DB² + EB²
ED² = 270² + 360²
ED² = 72 900 + 129 600
ED² = 202 500
ED = √202 500
ED = 450
2)
Théorème de Thalès :
AE/BE = CD/BD
AE/360 = 20/270
AE = 20/270*360
AE ≈ 26,7 cm
AC/ED = BC/BD
AC/450 = 250/270
AC = 250/270*450
AC ≈ 416,7cm
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Bonjour,
1) DB = 250 + 20 = 270
Théorème de Pythagore :
ED² = DB² + EB²
ED² = 270² + 360²
ED² = 72 900 + 129 600
ED² = 202 500
ED = √202 500
ED = 450
2)
Théorème de Thalès :
AE/BE = CD/BD
AE/360 = 20/270
AE = 20/270*360
AE ≈ 26,7 cm
AC/ED = BC/BD
AC/450 = 250/270
AC = 250/270*450
AC ≈ 416,7cm