Bonjour, pouvez vous m’aidez à calculer :
(2y-4)(3y+3)
(-y+3)(8-y)
-(y+6)(2y+4)
Merci beaucoup
(2y-4)(3y+3)
(-y+3)(8-y)
-(y+6)(2y+4)
Merci beaucoup
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Bonjour,
(2y-4)(3y+3)
= 6y² +6y -12y -12
= 6y² -6y -12
(-y+3)(8-y)
= -8y +y² +24 -3y
= y² -11y +24
-(y+6)(2y+4)
= -( 2y² +4y +12y +24)
= - 2y² -4y -12y -24
= -2y² -16y -24