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Louise93
@Louise93
May 2019
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Bonjour, Pouvez vous m'aidez à l'exercice 6et 12. S'il vous plaît? C'est pour demain. Merci. 4eme physique.
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MonsieurFirdown
Verified answer
Bonjour
6
♧1. On a : a. 1 200 km/h ≈ 333,3 m/s , donc ce trzin parcourt environ 333 m en 1 s
♧2. On a : v = d/t d'où t = d/v = 700/1200 = 0,58 h d'où 0,58×60 = 35 min
Voilà ^^
1 votes
Thanks 1
Louise93
Merci
Louise93
Tu pourrais m'aider pour la 12
MonsieurFirdown
;)
Louise93
stp
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Bonjour6
♧1. On a : a. 1 200 km/h ≈ 333,3 m/s , donc ce trzin parcourt environ 333 m en 1 s
♧2. On a : v = d/t d'où t = d/v = 700/1200 = 0,58 h d'où 0,58×60 = 35 min
Voilà ^^