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Solenezut
@Solenezut
April 2019
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Bonjour, pouvez vous m'aidez à résoudre cette équation ? Merci d'avance
-2x^(2) + x + 3 = 0
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Aftershock
-2x²+x+3 = 0
Δ = b²-4ac
Δ = 1²-4*(-2)*3
Δ = 25
Δ > 0 donc l'équation admet deux racines distinctes x1et x2
x1 =
(-b+√Δ)/2a
x1 = (-1+√25)/2*(-2)
x1 = 4/(-4)
x1 = -1
x2 = (-b+√Δ)/2a
x2 = (-1-√25)/2*(-2)
x2 = -6/(-4)
x2 = 3/2
L'équation admet le couple de solutions
S = {-1 ; 3/2}
2 votes
Thanks 1
Solenezut
Merci beaucoup, je ne suis qu'en seconde mais si j'ai bien compris c'est la méthode delta que vous utilisez non ?
Aftershock
Oui
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Δ = b²-4ac
Δ = 1²-4*(-2)*3
Δ = 25
Δ > 0 donc l'équation admet deux racines distinctes x1et x2
x1 = (-b+√Δ)/2a
x1 = (-1+√25)/2*(-2)
x1 = 4/(-4)
x1 = -1
x2 = (-b+√Δ)/2a
x2 = (-1-√25)/2*(-2)
x2 = -6/(-4)
x2 = 3/2
L'équation admet le couple de solutions S = {-1 ; 3/2}